MUST READ APTITUDE TRICKS
First of all to apply these tricks you will have to remember square of numbers from 1-30.
1* 1
2* 4
3* 9
4* 16
5* 25
6* 36
7* 49
8* 64
9* 81
10* 100
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11* 121
12* 144
13* 169
14* 196
15* 225
16* 256
17* 289
18* 324
19* 361
20* 400
|
21* 441
22* 484
23* 529
24* 576
25* 625
26* 676
27* 729
28* 784
29* 841
30* 900
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How to calculate the square of a number close to 50.
Tricks= First find how much its excess or less from 50.
Like : 54( its 54-50=4 excess)
46 (its 50-46=4 less)
72(its 72-50= 22 excess)
38(its 50-38=12 less)
In case of excess: add these excess number to 25.........like 54,72 all are greater then 50.
Like in case of 54 we will add 4 to 25 i.e 25+4=29
Now square the excess number i.e 4^2=16
So finally square of 54^ will be= 2916
In case of less : subtract less number from 25........... like 46, 38 all are less then 50.
Like in case of 46 we will subtract 4 from 25 i.e 25-4=21
Now square the less number i.e 4^2=16
So finally square of 46^2 will be= 2116
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Now square of number close to 100
Its very simple, just add the excess or subtract the less number from itself then calculate the square of excess or less number and add it at last.
Like 104, 4 excess from 100 so add 4 to 104 i.e 104+4=108.
and square of excess number i.e 4^2=16
So finally square of 104^2=10816.
Now lets calculate the square of 96.
Its 4 less from 100 so we will subtract 4 from it i.e 96-4=92
Square less number i.e 4^2=16
So finally square of 96^2=9216
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Now how to find unit digit of any number
first note these idea that
1^(any no)=1
5^(any no)=5
6^(any no)=6
4^(odd)=4
4^(even)=6
9^(odd)=9
9^(even)=1
And even number like (2,4,6,8)^4k=6
And odd number like (1,3,7,9)^4k=1
Here 4k means multiple of 4.
Here 4k means multiple of 4.
Now find out the unit digit of 324^337
4^(odd)=4
So answer will be 4.
find out the unit digit of 2462^72
2^(4*18)=6
So answer will be 6.
find out the unit digit of 7^73376
Since 76 is divisible by 4 i.e 3376 is a multiple of 4.
So, 7^(4k)=1
So answer will be 1.
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Now Calculate last two digit.
In case of number which have 1 at unit place, then the last two digit can be easily find out by keeping the unit place as 1 and multiply the decimal digit with unit digit of power.
For example :
Last two digit of 3481^(7788)?
As i mentioned that unit digit will be 1 of any number containing 1 in its unit place.
Now decimal digit of number i.e 3481 is 8
Now unit digit of power i.e 7788 is 8
Now multiply these two number 8*8=64
So last two digit will be = 641
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Now as we know that any odd number i.e 1,3,7,9 gives 1 at unit digit if power of number will be a multiple of 4 i.e 4k.
And after getting 1 at unit place we can easily find out the last two digit which is shown just above of it.
Find last two digit of 13^44?
Sol : Now break power in a multiple of 4 i.e 4*11
Now (13^(4))^11
Now Calculate 13^4......
First calculate 13^2=169 only take last two digit of it. i.e 69
Now calculate 69^2=excess number from 50 is 19 and 19^2=61
So 13^4 gives 61 at last two digit
So 13^4 gives 61 at last two digit
Now 61^11=As unit digit is one so unit place will be 1 and we will multiply the decimal digit of number i.e 6 to the unit digit of power which is 1, 6*1=6
So last two digit of 13^44=61
* Find out the last two digit of 87^5?
To get the answer of it calculate 87^4 and then multiply it by 87 again, we will get your answer.
To get the answer of it calculate 87^4 and then multiply it by 87 again, we will get your answer.