HOW TO FIND LAST TWO DIGIT IN POWER OF EVEN NUMBERS
To find out the last two digit first note some tips
(2^10)^odd number=24 (Last two digit)
(2^10)^even number=76 (Last two digit)
And product of 76 with any power of two will be equal to that number i.e last two digit.
For example : 76 * 2^2=04 will be the last two digit
76 * 2^3=08 will be the last two digit
76 * 2^4=16 will be the last two digit
76 * 2^5=32 will be the last two digit
76 * 2^6=64 will be the last two digit
76 * 2^7=28 will be the last two digit
76 * 2^8=56 will be the last two digit
76 * 2^9=12 will be the last two digit
76 * 2^10=24 will be the last two digit
* Now find out the last two digit of 2^84?
Sol : 2^84=(2^10)^8 * 2^4
=(2^10)^even number [i.e 8] * 2^4 [As we know (2^10)^even number=76 ]
=76 * 2^4
=2^4
=16 Last two digit.
* Find out the last two digit of 2^11283?
Sol :
2^11283=2^11280 * 2^3
=(2^10)^1128 * 2^3 [Since 1128 is even number so it will give 76]
=76 * 2^3
=08 Answer
* Find out the last two digit of 2^5433?
Sol :
2^5433=(2^10)^543 * 2^3 [Since 543 is odd number so it will give 24]
=24 * 08
=92 Last two digit